0=1.05t^2-50t-150

Solution for 0=1.05t^2-50t-150 equation:

0=1.05t^2-50t-150

We move all terms to the left:

0-(1.05t^2-50t-150)=0

We add all the numbers together, and all the variables

-(1.05t^2-50t-150)=0

We get rid of parentheses

-1.05t^2+50t+150=0

a = -1.05; b = 50; c = +150;
Δ = b2-4ac
Δ = 502-4·(-1.05)·150
Δ = 3130
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(50)-\sqrt{3130}}{2*-1.05}=\frac{-50-\sqrt{3130}}{-2.1}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(50)+\sqrt{3130}}{2*-1.05}=\frac{-50+\sqrt{3130}}{-2.1}
$